# Stoichiometry Worksheet Step by Step

Stoichiometry problems could be a little bit difficult especially if you don’t the basics of the calculations but with this piece on stoichiometry worksheet. I laid the foundations of Stoichiometry calculations with step-by-step tutorials on different categories of stoichiometry.

This stoichiometry worksheet is simply a guide to help us understand the full concept of stoichiometry calculations.

#### The worksheet is broken down into five (5) sections

1. Mole to Mole stoichiometry
1. Mole to mass stoichiometry
1. Mass to Mass Stoichiometry
1. Mass to volume stoichiometry
1. Volume to volume stoichiometry

I’ll do two examples on each category before the practice questions on same category.

It is important to follow the steps so to be able to have a full grasp of the concept and solve any stoichiometry problem.

## Stoichiometry Worksheet Mole to Mole Stoichiometry

In mole-to-mole Stoichiometry, you simply follow the step-by-step method of solving stoichiometry mole to mole stoichiometry which involves;

I. Balance the chemical equation

II. Compare the mole ratios

Example 1

How many moles of carbon iv oxide are produced by 3.5 moles of carbon burning in oxygen.

C+O2====CO2

Solution

If 1 mole of Carbon ===1 mole of CO2

3.3 moles of carbon == X

X= 3.3 x 1 = 3.3 moles if carbon IV oxide

Example 2

What number of moles of Hydrogen will yield 4.5 moles of Ammonia?

N2+ 3H2====2NH3

Solution

3 moles of H2===2 moles of NH3

4.5 moles of H2== X

X= 4.5 X 2 / 3

X= 3 moles of NH3

### Stoichiometry Worksheet for Mole-Mole Stoichiometry

Practice 1

How many moles of carbon II oxide will be required to burn completely in oxygen to produce 3.5 moles of carbon IV oxide?

2CO + O2===2CO2

Practice 2

What number of moles of nitrogen II oxide could be formed from 2.4 moles of nitrogen reaction with oxygen?

N2 + O2====2NO

Practice 3

Study this equation

Mg + 2HCl ====MgCl2 + H2

If 3.3 moles of magnesium reacted, what number of moles of hydrogen gas would be evolved?

Practice 4

How many moles of phosphorus III oxide can be gotten by the reaction of phosphorus with oxygen?

P4 + 3O2 ===2P2O3

## Stoichiometry Worksheet for Mole-to-Mass Stoichiometry

In mole-to-mass Stoichiometry, the guideline is almost the same.

You start by;

1. Crosschecking the balanced chemical equation
1. Compare the mole ratio.
1. Use stoichiometry conversion and change the mole to mass

Example 1

What mass of sulphur VI oxide would be evolved by the combustion of 0.5 mole of sulphur IV oxide with oxygen.

2SO2 + O2====2SO3

Solution

Using the balanced equation

2 moles of SO2====2 moles of SO3

0.5 mole of SO2=== X

X= 0.5 x 2 /2 = 0.5 mole of SO3

Convert the mole to mass

1 mole of SO3 = 80g

0.5 mole of SO3 = x

X = 0.5 mole X 80 grams /1 mole= 40 grams of sulphur VI oxide

Example 2

What mass of methane will burn with 3.3 moles of oxygen according to the equation below;

CH4 + 2O2 ==== CO2 + 2H2O

Solution

1 mole of CH4 ===== 2 moles of O2

X moles of CH4 ==== 3.3 moles of O2

X = 1 mole X 3.3 moles / 2 moles = 1.65 mole

Convert the moles to mass

1 mole of CH4 === 16 grams

1.65 mole of CH4 ==== X

X = 1.65 mole x 16 grams / 1 mole = 26.4 grams of Methane

### Stoichiometry Worksheet for Mole-Mass Stoichiometry

Practice 1

What mass of Nitrogen Fluoride will be gotten by the reaction of 2.7 moles of Nitrogen

N2 + 3F2 ==== 2NF3

Practice 2

What mass of carbon IV oxide will be evolved by the decomposition of 4.5 moles of magnesium trioxocarbonate IV.

MgCO3 ====MgO + CO2

Practice 3

What mass of copper II nitrate will be gotten by the reaction of 1.7 moles of silver nitrate reacting with copper?

2AgNO3 + Cu ===Cu(NO3)2 + 2Ag

Practice 4

What mass of Aluminium chloride is produced by the reaction of 10 moles of Aluminium?

2Al +6HCl ==== 3H2 + 2AlCl3

## Stoichiometry Worksheet for Mole-to-Volume Stoichiometry

The guideline in solving the mole to volume stoichiometry is same as other categories so I will quickly dive into the calculation.

Example 1

Calculate the volume of steam evolved by reacting 8.2 moles of Hydrogen?

2H2+ O2 ====2H2

Solution

2H2+ O2 ====2H2

2 moles of Hydrogen ==== 2 moles of steam

8.2 moles of Hydrogen ==== x

X = 8.2 moles x 2 moles / 2 moles

X = 8.2 moles of steam

Since 1 mole of steam === 22.4 Litres

8.2 moles ==== X

X = 8.2 x 22.4 / 1 = 183.68 litres

Example 2

What volume of Carbon monoxide would be evolved by burning 3 moles of carbon incompletely in oxygen?

C + O2 === 2CO

Solution

1 mole of carbon ===2 moles of Carbon monoxide

3 moles of Carbon == x

X =3 x 2 = 6 moles of Carbon monoxide

Since 1 mole of CO== 22.4 litres

6 moles of CO ==x

X = 6 X 22.4 = 134.4 Litres

### Stoichiometry Worksheet Mole-Volume stoichiometry

Practice 1

If 3 moles of Magnesium reacted with Hydrochloric acid, what volume of chlorine gas will be evolved?

Mg + 2HCl====MgCl2 + H2

Practice 2

2NaF + Br2 à 2NaBr + F2

What volume of fluorine gas would be evolved by 2 moles of sodium fluoride?

Practice 3

What volume of nitrogen fluoride will be evolved by the reaction of 7.2 moles of Nitrogen in the below;

N2 + 3F2 === 2NF3

Practice 4

Calculate the volume of nitrogen II oxide evolved by the reaction of 5.6 moles of Ammonia in Oxygen?

4NH3 + 5O2 === 4NO + 6H2

## Stoichiometry Worksheet for Mass-to-Mass Stoichiometry

The step-by-step method in mass-to-mass stoichiometry is very simple. You just convert the moles from the coefficient of reactants and products to mass and solve the mass of the required.

Stoichiometry worksheet mass-mass problems are very easy to solve if you can follow my stepwise method.

Example 1

What mass of oxygen is evolved by the decomposition of 56 grams of sodium trioxnitrate V?

2NaNO3 ====2NaNO2 + O2

Solution

2 moles of NaNO3 ===== 1 mole of O2

Converting to mass

85 grams of NaNO3 === 32 grams of O2

56 grams of NaNO3 ===== X

X = 56 x 32 /85

X = 21.08 grams of oxygen

Example 2

What mass of carbon IV oxide would be evolved by the combustion of 4O grams of propane in Oxygen

2C3H6 + 9O2===6CO2 + 6H2

Solution

2 moles of C3H6 ==== 6 moles of CO2

Convert the moles to mass

84 grams of C3H6 ==== 264 grams of CO2

40 grams of C3H6==== X

X= 40 x 264/84 = 125.71 grams of CO2

### Stoichiometry concept mass -mass stoichiometry

Practice 1

Na2CO3 + 2HCl → 2NaCl + H2O + CO2

What mass of sodium chloride is produced by reacting 23.5 grams of sodium carbonate?

Practice 2

What mass of steam is evolved by burning 78.9 grams of Benzoic acid?

2C7H6O2 + 15O2 === 14CO2 + 6H2

Practice 3

What mass of calcium hydroxide will precipitate 45.6 grams of Aluminium hydroxide?

Al2(SO4)3 + 3Ca(OH)2 === 2Al(OH)3 + 3CaSO4

Practice 4

What mass of sulphuric acid will produce 18.7 grams of Hydrogen sulphide?

H2SO4 + 8HI → H2S + 4I2 + 4H2

### Stoichiometry Worksheet for Volume-to-Volume Stoichiometry

Volume to volume stoichiometry is very easy since we only need to convert the mole of the gaseous reactant or product to the molar volume.

Example 1

What volume of hydrazine is evolved b reacting 20 litres of Nitrogen?

N2 + 2H2 ===== N2H4

Solution

1 mole of N2 ===== 1 mole of N2H4

22.4 litres of N2 === 22.4 litres of N2H4

20 litres of N2 ==== X

X = 20 litres x 22.4 litres /22.4 litres = 20 litres of N2H4

Example 2

What volume of hydrogen chloride gas is formed by the reaction of 20 dm3 of hydrogen?

H2 + Cl2 ====2HCl

Solution

1 mole of Hydrogen ===== 2 moles of hydrogen chloride gas

22.4 dm3 of Hydrogen ===== 44.8 dm3 of Hydrogen chloride gas

20 dm3 of Hydrogen ====== X

X= 20 x 44.8 / 22.4 = 40 dm3 of Hydrogen chloride gas

### Stoichiometry worksheet volume -volume stoichiometry

Practice 1

What volume of ammonia is evolved by reacting 15.7 litres of nitrogen with hydrogen?

N2 + 3H2 =====2NH3

Practice 2

What volume of oxygen is required in burning carbon to form 14.4 litres of carbon IV oxide?

C + O2====CO

Practice 3

What volume of carbon II oxide is converted to 30 litres of carbon IV oxide?

CO + O2 ===CO2

Practice 4

What volume of Ethene is needed to form 30 liters of ethane on reaction with hydrogen?

C2H4 + H2 ====C2H6

Finally. solving stoichiometry isa skill that involves following the guideline and practicing with multiple questions and that’s why i broke the concept down into categories for easy grasp of the content.