Stoichiometry Worksheet Step by Step
Stoichiometry problems could be a little bit difficult especially if you don’t the basics of the calculations but with this piece on stoichiometry worksheet. I laid the foundations of Stoichiometry calculations with step-by-step tutorials on different categories of stoichiometry.
This stoichiometry worksheet is simply a guide to help us understand the full concept of stoichiometry calculations.
The worksheet is broken down into five (5) sections
- Mole to Mole stoichiometry
- Mole to mass stoichiometry
- Mass to Mass Stoichiometry
- Mass to volume stoichiometry
- Volume to volume stoichiometry
I’ll do two examples on each category before the practice questions on same category.
It is important to follow the steps so to be able to have a full grasp of the concept and solve any stoichiometry problem.
Stoichiometry Worksheet Mole to Mole Stoichiometry
In mole-to-mole Stoichiometry, you simply follow the step-by-step method of solving stoichiometry mole to mole stoichiometry which involves;
I. Balance the chemical equation
II. Compare the mole ratios
Example 1
How many moles of carbon iv oxide are produced by 3.5 moles of carbon burning in oxygen.
C+O2====CO2
Solution
If 1 mole of Carbon ===1 mole of CO2
3.3 moles of carbon == X
X= 3.3 x 1 = 3.3 moles if carbon IV oxide
Example 2
What number of moles of Hydrogen will yield 4.5 moles of Ammonia?
N2+ 3H2====2NH3
Solution
3 moles of H2===2 moles of NH3
4.5 moles of H2== X
X= 4.5 X 2 / 3
X= 3 moles of NH3
Stoichiometry Worksheet for Mole-Mole Stoichiometry
Practice 1
How many moles of carbon II oxide will be required to burn completely in oxygen to produce 3.5 moles of carbon IV oxide?
2CO + O2===2CO2
Practice space |
Practice 2
What number of moles of nitrogen II oxide could be formed from 2.4 moles of nitrogen reaction with oxygen?
N2 + O2====2NO
Practice space |
Practice 3
Study this equation
Mg + 2HCl ====MgCl2 + H2
If 3.3 moles of magnesium reacted, what number of moles of hydrogen gas would be evolved?
Practice space |
Practice 4
How many moles of phosphorus III oxide can be gotten by the reaction of phosphorus with oxygen?
P4 + 3O2 ===2P2O3
Practice space |
Stoichiometry Worksheet for Mole-to-Mass Stoichiometry
In mole-to-mass Stoichiometry, the guideline is almost the same.
You start by;
- Crosschecking the balanced chemical equation
- Compare the mole ratio.
- Use stoichiometry conversion and change the mole to mass
Example 1
What mass of sulphur VI oxide would be evolved by the combustion of 0.5 mole of sulphur IV oxide with oxygen.
2SO2 + O2====2SO3
Solution
Using the balanced equation
2 moles of SO2====2 moles of SO3
0.5 mole of SO2=== X
X= 0.5 x 2 /2 = 0.5 mole of SO3
Convert the mole to mass
1 mole of SO3 = 80g
0.5 mole of SO3 = x
X = 0.5 mole X 80 grams /1 mole= 40 grams of sulphur VI oxide
Example 2
What mass of methane will burn with 3.3 moles of oxygen according to the equation below;
CH4 + 2O2 ==== CO2 + 2H2O
Solution
1 mole of CH4 ===== 2 moles of O2
X moles of CH4 ==== 3.3 moles of O2
X = 1 mole X 3.3 moles / 2 moles = 1.65 mole
Convert the moles to mass
1 mole of CH4 === 16 grams
1.65 mole of CH4 ==== X
X = 1.65 mole x 16 grams / 1 mole = 26.4 grams of Methane
Stoichiometry Worksheet for Mole-Mass Stoichiometry
Practice 1
What mass of Nitrogen Fluoride will be gotten by the reaction of 2.7 moles of Nitrogen
N2 + 3F2 ==== 2NF3
Practice space |
Practice 2
What mass of carbon IV oxide will be evolved by the decomposition of 4.5 moles of magnesium trioxocarbonate IV.
MgCO3 ====MgO + CO2
Practice space |
Practice 3
What mass of copper II nitrate will be gotten by the reaction of 1.7 moles of silver nitrate reacting with copper?
2AgNO3 + Cu ===Cu(NO3)2 + 2Ag
Practice space |
Practice 4
What mass of Aluminium chloride is produced by the reaction of 10 moles of Aluminium?
2Al +6HCl ==== 3H2 + 2AlCl3
Practice space |
Stoichiometry Worksheet for Mole-to-Volume Stoichiometry
The guideline in solving the mole to volume stoichiometry is same as other categories so I will quickly dive into the calculation.
Example 1
Calculate the volume of steam evolved by reacting 8.2 moles of Hydrogen?
2H2+ O2 ====2H2O
Solution
2H2+ O2 ====2H2O
2 moles of Hydrogen ==== 2 moles of steam
8.2 moles of Hydrogen ==== x
X = 8.2 moles x 2 moles / 2 moles
X = 8.2 moles of steam
Since 1 mole of steam === 22.4 Litres
8.2 moles ==== X
X = 8.2 x 22.4 / 1 = 183.68 litres
Example 2
What volume of Carbon monoxide would be evolved by burning 3 moles of carbon incompletely in oxygen?
C + O2 === 2CO
Solution
1 mole of carbon ===2 moles of Carbon monoxide
3 moles of Carbon == x
X =3 x 2 = 6 moles of Carbon monoxide
Since 1 mole of CO== 22.4 litres
6 moles of CO ==x
X = 6 X 22.4 = 134.4 Litres
Stoichiometry Worksheet Mole-Volume stoichiometry
Practice 1
If 3 moles of Magnesium reacted with Hydrochloric acid, what volume of chlorine gas will be evolved?
Mg + 2HCl====MgCl2 + H2
Practice space |
Practice 2
2NaF + Br2 à 2NaBr + F2
What volume of fluorine gas would be evolved by 2 moles of sodium fluoride?
Practice space |
Practice 3
What volume of nitrogen fluoride will be evolved by the reaction of 7.2 moles of Nitrogen in the below;
N2 + 3F2 === 2NF3
Practice space |
Practice 4
Calculate the volume of nitrogen II oxide evolved by the reaction of 5.6 moles of Ammonia in Oxygen?
4NH3 + 5O2 === 4NO + 6H2O
Practice space |
Stoichiometry Worksheet for Mass-to-Mass Stoichiometry
The step-by-step method in mass-to-mass stoichiometry is very simple. You just convert the moles from the coefficient of reactants and products to mass and solve the mass of the required.
Stoichiometry worksheet mass-mass problems are very easy to solve if you can follow my stepwise method.
Example 1
What mass of oxygen is evolved by the decomposition of 56 grams of sodium trioxnitrate V?
2NaNO3 ====2NaNO2 + O2
Solution
2 moles of NaNO3 ===== 1 mole of O2
Converting to mass
85 grams of NaNO3 === 32 grams of O2
56 grams of NaNO3 ===== X
X = 56 x 32 /85
X = 21.08 grams of oxygen
Example 2
What mass of carbon IV oxide would be evolved by the combustion of 4O grams of propane in Oxygen
2C3H6 + 9O2===6CO2 + 6H2O
Solution
2 moles of C3H6 ==== 6 moles of CO2
Convert the moles to mass
84 grams of C3H6 ==== 264 grams of CO2
40 grams of C3H6==== X
X= 40 x 264/84 = 125.71 grams of CO2
Stoichiometry concept mass -mass stoichiometry
Practice 1
Na2CO3 + 2HCl → 2NaCl + H2O + CO2
What mass of sodium chloride is produced by reacting 23.5 grams of sodium carbonate?
Practice space |
Practice 2
What mass of steam is evolved by burning 78.9 grams of Benzoic acid?
2C7H6O2 + 15O2 === 14CO2 + 6H2O
Practice space |
Practice 3
What mass of calcium hydroxide will precipitate 45.6 grams of Aluminium hydroxide?
Al2(SO4)3 + 3Ca(OH)2 === 2Al(OH)3 + 3CaSO4
Practice space |
Practice 4
What mass of sulphuric acid will produce 18.7 grams of Hydrogen sulphide?
H2SO4 + 8HI → H2S + 4I2 + 4H2O
Practice space |
Stoichiometry Worksheet for Volume-to-Volume Stoichiometry
Volume to volume stoichiometry is very easy since we only need to convert the mole of the gaseous reactant or product to the molar volume.
Example 1
What volume of hydrazine is evolved b reacting 20 litres of Nitrogen?
N2 + 2H2 ===== N2H4
Solution
1 mole of N2 ===== 1 mole of N2H4
22.4 litres of N2 === 22.4 litres of N2H4
20 litres of N2 ==== X
X = 20 litres x 22.4 litres /22.4 litres = 20 litres of N2H4
Example 2
What volume of hydrogen chloride gas is formed by the reaction of 20 dm3 of hydrogen?
H2 + Cl2 ====2HCl
Solution
1 mole of Hydrogen ===== 2 moles of hydrogen chloride gas
22.4 dm3 of Hydrogen ===== 44.8 dm3 of Hydrogen chloride gas
20 dm3 of Hydrogen ====== X
X= 20 x 44.8 / 22.4 = 40 dm3 of Hydrogen chloride gas
Stoichiometry worksheet volume -volume stoichiometry
Practice 1
What volume of ammonia is evolved by reacting 15.7 litres of nitrogen with hydrogen?
N2 + 3H2 =====2NH3
Practice space |
Practice 2
What volume of oxygen is required in burning carbon to form 14.4 litres of carbon IV oxide?
C + O2====CO2
Practice space |
Practice 3
What volume of carbon II oxide is converted to 30 litres of carbon IV oxide?
CO + O2 ===CO2
Practice space |
Practice 4
What volume of Ethene is needed to form 30 liters of ethane on reaction with hydrogen?
C2H4 + H2 ====C2H6
practice space |
Finally. solving stoichiometry isa skill that involves following the guideline and practicing with multiple questions and that’s why i broke the concept down into categories for easy grasp of the content.