Stoichiometry Worksheet Step by Step 

Stoichiometry problems could be a little bit difficult especially if you don’t the basics of the calculations but with this piece on stoichiometry worksheet. I laid the foundations of Stoichiometry calculations with step-by-step tutorials on different categories of stoichiometry. 

This stoichiometry worksheet is simply a guide to help us understand the full concept of stoichiometry calculations. 
 

The worksheet is broken down into five (5) sections 

1. Mole to Mole stoichiometry  

2. Mole to mass stoichiometry  

3. Mass to Mass Stoichiometry  

4. Mass to volume stoichiometry  

5. Volume to volume stoichiometry  

I’ll do two examples on each category before the practice questions on same category.  

It is important to follow the steps so to be able to have a full grasp of the concept and solve any stoichiometry problem. 
 

Stoichiometry Worksheet Mole to Mole Stoichiometry 

In mole-to-mole Stoichiometry, you simply follow the step-by-step method of solving stoichiometry mole to mole stoichiometry which involves; 

I. Balance the chemical equation  

II. Compare the mole ratios  

Example 1 

How many moles of carbon iv oxide are produced by 3.5 moles of carbon burning in oxygen.  

C+O₂====CO₂ 

Solution  

If 1 mole of Carbon ===1 mole of CO₂ 

3.3 moles of carbon == X 

X= 3.3 x 1 = 3.3 moles if carbon IV oxide  

Example 2 

What number of moles of Hydrogen will yield 4.5 moles of Ammonia? 

N₂+ 3H₂====2NH₃ 

Solution  

3 moles of H₂===2 moles of NH₃ 

4.5 moles of H₂== X 

X= 4.5 X 2 / 3 

X= 3 moles of NH₃ 

Stoichiometry Worksheet for Mole-Mole Stoichiometry  

Practice 1 

How many moles of carbon II oxide will be required to burn completely in oxygen to produce 3.5 moles of carbon IV oxide? 

2CO + O₂===2CO₂ 

Practice space

Practice 2 

What number of moles of nitrogen II oxide could be formed from 2.4 moles of nitrogen reaction with oxygen? 

N₂ + O₂====2NO 

Practice space

Practice 3 

Study this equation 

Mg + 2HCl ====MgCl₂ + H₂ 

If 3.3 moles of magnesium reacted, what number of moles of hydrogen gas would be evolved? 

Practice space

Practice 4 

How many moles of phosphorus III oxide can be gotten by the reaction of phosphorus with oxygen? 

P₄ + 3O₂ ===2P₂O₃ 

Practice space

Stoichiometry Worksheet for Mole-to-Mass Stoichiometry  

In mole-to-mass Stoichiometry, the guideline is almost the same. 

You start by; 

1. Crosschecking the balanced chemical equation 

2. Compare the mole ratio. 

3. Use stoichiometry conversion and change the mole to mass 

Example 1 

What mass of sulphur VI oxide would be evolved by the combustion of 0.5 mole of sulphur IV oxide with oxygen. 

2SO₂ + O₂====2SO₃ 

Solution  

Using the balanced equation  

2 moles of SO₂====2 moles of SO₃ 

0.5 mole of SO₂=== X 

X= 0.5 x 2 /2 = 0.5 mole of SO₃ 

Convert the mole to mass  

1 mole of SO₃ = 80g 

0.5 mole of SO₃ = x  

X = 0.5 mole X 80 grams /1 mole= 40 grams of sulphur VI oxide 

Example 2 

What mass of methane will burn with 3.3 moles of oxygen according to the equation below; 

CH₄ + 2O₂ ==== CO₂ + 2H₂O 

Solution 

1 mole of CH₄ ===== 2 moles of O₂ 

X moles of CH₄ ==== 3.3 moles of O₂ 

X = 1 mole X 3.3 moles / 2 moles = 1.65 mole 

Convert the moles to mass 

1 mole of CH₄ === 16 grams 

1.65 mole of CH₄ ==== X 

X = 1.65 mole x 16 grams / 1 mole = 26.4 grams of Methane 

Stoichiometry Worksheet for Mole-Mass Stoichiometry 

Practice 1 

What mass of Nitrogen Fluoride will be gotten by the reaction of 2.7 moles of Nitrogen 

N₂ + 3F₂ ==== 2NF₃ 

Practice space

Practice 2 

What mass of carbon IV oxide will be evolved by the decomposition of 4.5 moles of magnesium trioxocarbonate IV. 

MgCO₃ ====MgO + CO₂ 

Practice space

Practice 3 

What mass of copper II nitrate will be gotten by the reaction of 1.7 moles of silver nitrate reacting with copper? 

2AgNO₃ + Cu ===Cu(NO₃)₂ + 2Ag 

Practice space

Practice 4 

What mass of Aluminium chloride is produced by the reaction of 10 moles of Aluminium? 

2Al +6HCl ==== 3H₂ + 2AlCl₃ 

Practice space

Stoichiometry Worksheet for Mole-to-Volume Stoichiometry 

The guideline in solving the mole to volume stoichiometry is same as other categories so I will quickly dive into the calculation. 

Example 1 

Calculate the volume of steam evolved by reacting 8.2 moles of Hydrogen? 

2H₂+ O₂ ====2H₂O 

Solution  

2H₂+ O₂ ====2H₂O 

2 moles of Hydrogen ==== 2 moles of steam 

8.2 moles of Hydrogen ==== x 

X = 8.2 moles x 2 moles / 2 moles  

X = 8.2 moles of steam  

Since 1 mole of steam === 22.4 Litres 

8.2 moles ==== X 

X = 8.2 x 22.4 / 1 = 183.68 litres 

Example 2 

What volume of Carbon monoxide would be evolved by burning 3 moles of carbon incompletely in oxygen? 

C + O₂ === 2CO 

Solution  

1 mole of carbon ===2 moles of Carbon monoxide  

3 moles of Carbon == x  

X =3 x 2 = 6 moles of Carbon monoxide 

Since 1 mole of CO== 22.4 litres 

6 moles of CO ==x  

X = 6 X 22.4 = 134.4 Litres 

Stoichiometry Worksheet Mole-Volume stoichiometry

Practice 1 

If 3 moles of Magnesium reacted with Hydrochloric acid, what volume of chlorine gas will be evolved? 

Mg + 2HCl====MgCl₂ + H₂ 

Practice space

Practice 2 

2NaF + Br₂ à 2NaBr + F₂ 

What volume of fluorine gas would be evolved by 2 moles of sodium fluoride? 

Practice space

Practice 3 

What volume of nitrogen fluoride will be evolved by the reaction of 7.2 moles of Nitrogen in the below; 

N₂ + 3F₂ === 2NF₃ 

Practice space

Practice 4 

Calculate the volume of nitrogen II oxide evolved by the reaction of 5.6 moles of Ammonia in Oxygen? 

4NH₃ + 5O₂ === 4NO + 6H₂O 

Practice space

Stoichiometry Worksheet for Mass-to-Mass Stoichiometry 

The step-by-step method in mass-to-mass stoichiometry is very simple. You just convert the moles from the coefficient of reactants and products to mass and solve the mass of the required.

Stoichiometry worksheet mass-mass problems are very easy to solve if you can follow my stepwise method. 

Example 1 

What mass of oxygen is evolved by the decomposition of 56 grams of sodium trioxnitrate V? 

2NaNO₃ ====2NaNO₂ + O₂ 

Solution  

2 moles of NaNO₃ ===== 1 mole of O₂ 

Converting to mass  

85 grams of NaNO₃ === 32 grams of O₂ 

56 grams of NaNO₃ ===== X 

X = 56 x 32 /85  

X = 21.08 grams of oxygen 

Example 2 

What mass of carbon IV oxide would be evolved by the combustion of 4O grams of propane in Oxygen 

2C₃H₆ + 9O₂===6CO₂ + 6H₂O 

Solution  

2 moles of C₃H₆ ==== 6 moles of CO₂ 

Convert the moles to mass 

84 grams of C₃H₆ ==== 264 grams of CO₂ 

40 grams of C₃H₆==== X 

X= 40 x 264/84 = 125.71 grams of CO₂ 

Stoichiometry concept mass -mass stoichiometry

Practice 1 

Na₂CO₃ + 2HCl → 2NaCl + H₂O + CO₂ 

What mass of sodium chloride is produced by reacting 23.5 grams of sodium carbonate? 

Practice space

Practice 2 

What mass of steam is evolved by burning 78.9 grams of Benzoic acid? 

2C₇H₆O₂ + 15O₂ === 14CO₂ + 6H₂O 

Practice space

Practice 3 

What mass of calcium hydroxide will precipitate 45.6 grams of Aluminium hydroxide? 

Al₂(SO₄)₃ + 3Ca(OH)₂ === 2Al(OH)₃ + 3CaSO₄ 

Practice space

Practice 4 

What mass of sulphuric acid will produce 18.7 grams of Hydrogen sulphide? 

H₂SO₄ + 8HI → H₂S + 4I₂ + 4H₂O 

Practice space

Stoichiometry Worksheet for Volume-to-Volume Stoichiometry 

Volume to volume stoichiometry is very easy since we only need to convert the mole of the gaseous reactant or product to the molar volume. 

Example 1 

What volume of hydrazine is evolved b reacting 20 litres of Nitrogen? 

N₂ + 2H₂ ===== N₂H₄ 

_Solution  

1 mole of N₂ ===== 1 mole of N₂H₄ 

22.4 litres of N₂ === 22.4 litres of N₂H₄ 

20 litres of N₂ ==== X 

X = 20 litres x 22.4 litres /22.4 litres = 20 litres of N₂H₄ 

Example 2 

What volume of hydrogen chloride gas is formed by the reaction of 20 dm³ of hydrogen? 

H₂ + Cl₂ ====2HCl 

Solution  

1 mole of Hydrogen ===== 2 moles of hydrogen chloride gas 

22.4 dm³ of Hydrogen ===== 44.8 dm³ of Hydrogen chloride gas 

20 dm³ of Hydrogen ====== X 

X= 20 x 44.8 / 22.4 = 40 dm³ of Hydrogen chloride gas 

Stoichiometry worksheet volume -volume stoichiometry

Practice 1 

What volume of ammonia is evolved by reacting 15.7 litres of nitrogen with hydrogen? 

N₂ + 3H₂ =====2NH₃ 

Practice space

Practice 2 

What volume of oxygen is required in burning carbon to form 14.4 litres of carbon IV oxide? 

C + O₂====CO₂  

Practice space

Practice 3 

What volume of carbon II oxide is converted to 30 litres of carbon IV oxide? 

CO + O₂ ===CO₂ 

Practice space

Practice 4 

What volume of Ethene is needed to form 30 liters of ethane on reaction with hydrogen? 

C₂H₄ + H₂ ====C₂H₆ 

practice space

Finally. solving stoichiometry isa skill that involves following the guideline and practicing with multiple questions and that’s why i broke the concept down into categories for easy grasp of the content.