# Stoichiometry Worksheet Step by Step

Stoichiometry problems could be a little bit difficult especially if you don’t the basics of the calculations but with this piece on stoichiometry worksheet. I laid the foundations of Stoichiometry calculations with step-by-step tutorials on different categories of stoichiometry.

This stoichiometry worksheet is simply a guide to help us understand the full concept of stoichiometry calculations.

#### The worksheet is broken down into five (5) sections

*Mole to Mole stoichiometry*

*Mole to mass stoichiometry*

*Mass to Mass Stoichiometry*

*Mass to volume stoichiometry*

*Volume to volume stoichiometry*

I’ll do two examples on each category before the practice questions on same category.

It is important to follow the steps so to be able to have a full grasp of the concept and solve any stoichiometry problem.

## Stoichiometry Worksheet **Mole to Mole Stoichiometry **

In mole-to-mole Stoichiometry, you simply follow the step-by-step method of solving stoichiometry mole to mole stoichiometry which involves;

*I. Balance the chemical equation *

*II. Compare the mole ratios *

Example 1

How many moles of carbon iv oxide are produced by 3.5 moles of carbon burning in oxygen.

C+O_{2}====CO_{2}

**Solution**

If 1 mole of Carbon ===1 mole of CO_{2}

3.3 moles of carbon == X

X= 3.3 x 1 = 3.3 moles if carbon IV oxide

Example 2

What number of moles of Hydrogen will yield 4.5 moles of Ammonia?

N_{2}+ 3H_{2}====2NH_{3}

**Solution**

3 moles of H_{2}===2 moles of NH_{3}

4.5 moles of H_{2}== X

X= 4.5 X 2 / 3

X= 3 moles of NH_{3}

*Stoichiometry Worksheet for Mole-Mole Stoichiometry *

*Stoichiometry Worksheet for Mole-Mole Stoichiometry*

Practice 1

How many moles of carbon II oxide will be required to burn completely in oxygen to produce 3.5 moles of carbon IV oxide?

2CO + O_{2}===2CO_{2}

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Practice 2

What number of moles of nitrogen II oxide could be formed from 2.4 moles of nitrogen reaction with oxygen?

N_{2 }+ O_{2}====2NO

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Practice 3

Study this equation

Mg + 2HCl ====MgCl_{2} + H_{2}

If 3.3 moles of magnesium reacted, what number of moles of hydrogen gas would be evolved?

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Practice 4

How many moles of phosphorus III oxide can be gotten by the reaction of phosphorus with oxygen?

P_{4 }+ 3O_{2 }===2P_{2}O_{3}

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## Stoichiometry Worksheet for Mole-to-Mass Stoichiometry

In mole-to-mass Stoichiometry, the guideline is almost the same.

You start by;

*Crosschecking the balanced chemical equation*

*Compare the mole ratio.*

*Use stoichiometry conversion and change the mole to mass*

Example 1

What mass of sulphur VI oxide would be evolved by the combustion of 0.5 mole of sulphur IV oxide with oxygen.

2SO_{2} + O_{2}====2SO_{3}

**Solution **

*Using the balanced equation *

*2 moles of SO*_{2}*====2 moles of SO*_{3}

*0.5 mole of SO*_{2}*=== X*

*X= 0.5 x 2 /2 = 0.5 mole of SO*_{3}

*Convert the mole to mass *

*1 mole of SO*_{3 }*= 80g*

*0.5 mole of SO*_{3}* = x *

*X = 0.5 mole X 80 grams /1 mole= 40 grams of sulphur VI oxide*

*Example 2*

*What mass of methane will burn with 3.3 moles of oxygen according to the equation below;*

*CH*_{4}* + 2O*_{2}* ==== CO*_{2}* + 2H*_{2}*O*

*Solution*

*1 mole of CH*_{4}* ===== 2 moles of O*_{2}

*X moles of CH*_{4 }*==== 3.3 moles of O*_{2}

*X = 1 mole X 3.3 moles / 2 moles = 1.65 mole*

*Convert the moles to mass*

*1 mole of CH*_{4}* === 16 grams*

*1.65 mole of CH*_{4}* ==== X*

*X = 1.65 mole x 16 grams / 1 mole = 26.4 grams of Methane*

*Stoichiometry Worksheet for Mole-Mass Stoichiometry*

*Stoichiometry Worksheet for Mole-Mass Stoichiometry*

Practice 1

What mass of Nitrogen Fluoride will be gotten by the reaction of 2.7 moles of Nitrogen

N_{2} + 3F_{2} ==== 2NF_{3}

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Practice 2

What mass of carbon IV oxide will be evolved by the decomposition of 4.5 moles of magnesium trioxocarbonate IV.

MgCO_{3} ====MgO + CO_{2}

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Practice 3

What mass of copper II nitrate will be gotten by the reaction of 1.7 moles of silver nitrate reacting with copper?

2AgNO_{3} + Cu ===Cu(NO_{3})_{2} + 2Ag

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Practice 4

What mass of Aluminium chloride is produced by the reaction of 10 moles of Aluminium?

2Al +6HCl ==== 3H_{2} + 2AlCl_{3}

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**Stoichiometry Worksheet for Mole-to-Volume Stoichiometry**

The guideline in solving the mole to volume stoichiometry is same as other categories so I will quickly dive into the calculation.

Example 1

Calculate the volume of steam evolved by reacting 8.2 moles of Hydrogen?

2H_{2}+ O_{2} ====2H_{2}O

Solution

2H_{2}+ O_{2} ====2H_{2}O

2 moles of Hydrogen ==== 2 moles of steam

8.2 moles of Hydrogen ==== x

X = 8.2 moles x 2 moles / 2 moles

X = 8.2 moles of steam

Since 1 mole of steam === 22.4 Litres

8.2 moles ==== X

X = 8.2 x 22.4 / 1 = 183.68 litres

Example 2

What volume of Carbon monoxide would be evolved by burning 3 moles of carbon incompletely in oxygen?

C + O_{2} === 2CO

Solution

1 mole of carbon ===2 moles of Carbon monoxide

3 moles of Carbon == x

X =3 x 2 = 6 moles of Carbon monoxide

Since 1 mole of CO== 22.4 litres

6 moles of CO ==x

X = 6 X 22.4 = 134.4 Litres

*Stoichiometry Worksheet Mole-Volume stoichiometry*

Practice 1

If 3 moles of Magnesium reacted with Hydrochloric acid, what volume of chlorine gas will be evolved?

Mg + 2HCl====MgCl_{2} + H_{2}

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Practice 2

2NaF + Br_{2} à 2NaBr + F_{2}

What volume of fluorine gas would be evolved by 2 moles of sodium fluoride?

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Practice 3

What volume of nitrogen fluoride will be evolved by the reaction of 7.2 moles of Nitrogen in the below;

N_{2} + 3F_{2} === 2NF_{3}

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Practice 4

Calculate the volume of nitrogen II oxide evolved by the reaction of 5.6 moles of Ammonia in Oxygen?

4NH_{3} + 5O_{2} === 4NO + 6H_{2}O

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**Stoichiometry Worksheet for Mass-to-Mass Stoichiometry**

The step-by-step method in mass-to-mass stoichiometry is very simple. You just convert the moles from the coefficient of reactants and products to mass and solve the mass of the required.

Stoichiometry worksheet mass-mass problems are very easy to solve if you can follow my stepwise method.

Example 1

What mass of oxygen is evolved by the decomposition of 56 grams of sodium trioxnitrate V?

2NaNO_{3} ====2NaNO_{2} + O_{2}

**Solution**

2 moles of NaNO_{3} ===== 1 mole of O_{2}

Converting to mass

85 grams of NaNO_{3 }=== 32 grams of O_{2}

56 grams of NaNO_{3 }===== X

X = 56 x 32 /85

X = 21.08 grams of oxygen

Example 2

What mass of carbon IV oxide would be evolved by the combustion of 4O grams of propane in Oxygen

2C_{3}H_{6} + 9O_{2}===6CO_{2 }+ 6H_{2}O

Solution

2 moles of C_{3}H_{6 }==== 6 moles of CO_{2}

Convert the moles to mass

84 grams of C_{3}H_{6} ==== 264 grams of CO_{2}

40 grams of C_{3}H_{6}==== X

X= 40 x 264/84 = 125.71 grams of CO_{2}

*Stoichiometry concept mass -mass stoichiometry*

Practice 1

Na_{2}CO_{3} + 2HCl → 2NaCl + H_{2}O + CO_{2}

What mass of sodium chloride is produced by reacting 23.5 grams of sodium carbonate?

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Practice 2

What mass of steam is evolved by burning 78.9 grams of Benzoic acid?

2C_{7}H_{6}O_{2} + 15O_{2} === 14CO_{2} + 6H_{2}O

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Practice 3

What mass of calcium hydroxide will precipitate 45.6 grams of Aluminium hydroxide?

Al_{2}(SO_{4})_{3} + 3Ca(OH)_{2} === 2Al(OH)_{3} + 3CaSO_{4}

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Practice 4

What mass of sulphuric acid will produce 18.7 grams of Hydrogen sulphide?

H_{2}SO_{4} + 8HI → H_{2}S + 4I_{2} + 4H_{2}O

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*Stoichiometry Worksheet for Volume-to-Volume Stoichiometry*

Volume to volume stoichiometry is very easy since we only need to convert the mole of the gaseous reactant or product to the molar volume.

Example 1

What volume of hydrazine is evolved b reacting 20 litres of Nitrogen?

N_{2} + 2H_{2} ===== N_{2}H_{4}

_{Solution }

1 mole of N_{2} ===== 1 mole of N_{2}H_{4}

22.4 litres of N_{2} === 22.4 litres of N_{2}H_{4}

20 litres of N_{2 }==== X

X = 20 litres x 22.4 litres /22.4 litres = 20 litres of N_{2}H_{4}

Example 2

What volume of hydrogen chloride gas is formed by the reaction of 20 dm^{3} of hydrogen?

H_{2} + Cl_{2} ====2HCl

**Solution **

1 mole of Hydrogen ===== 2 moles of hydrogen chloride gas

22.4 dm^{3} of Hydrogen ===== 44.8 dm^{3} of Hydrogen chloride gas

20 dm^{3} of Hydrogen ====== X

X= 20 x 44.8 / 22.4 = 40 dm^{3} of Hydrogen chloride gas

*Stoichiometry worksheet volume -volume stoichiometry *

Practice 1

What volume of ammonia is evolved by reacting 15.7 litres of nitrogen with hydrogen?

N_{2} + 3H_{2} =====2NH_{3}

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Practice 2

What volume of oxygen is required in burning carbon to form 14.4 litres of carbon IV oxide?

C + O_{2}====CO_{2 }

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Practice 3

What volume of carbon II oxide is converted to 30 litres of carbon IV oxide?

CO + O_{2} ===CO_{2}

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Practice 4

What volume of Ethene is needed to form 30 liters of ethane on reaction with hydrogen?

C_{2}H_{4} + H_{2} ====C_{2}H_{6}

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Finally. solving stoichiometry isa skill that involves following the guideline and practicing with multiple questions and that’s why i broke the concept down into categories for easy grasp of the content.